The Russian club have issued a statement after repeated links to their Belgian midfielder.
Tottenham Hotspur may have to sell the family china if they want to sign Zenit St Petersburg midfielder Axel Witsel this summer, because the Belgian midfielder’s club have made it clear he is going nowhere this summer – reiterating his release clause in the process.
As reported by EuroFootball.ru, quoting national agency TACC, the Russian club, who are of course managed by former Tottenham Hotspur boss Andre Villas-Boas, have made it clear through their press service that the player will not be leaving, whilst reiterating his whopping release clause:
"Axel Witsel will remain a player of Zenit. His release clause has been repeatedly voiced and amounts to €100 million (£72.7 million)."
The announcement comes in the wake of The Telegraph’s report claiming that Spurs were also considering a move for the Belgian powerhouse, amid talk of their Victor Wanyama approach falling flat.
Reports in Italy, from Calcio Mercato, then went on to suggest Tottenham had bid €26 million (£18.9 million) for the player – which would have rightly got Tottenham fans excited.
However the Russian club are standing firm on the future of one of their marquee players, with Italian side AC Milan also sniffing around.
It seems they are more than happy to keep hold of Witsel for now and that spurs may have to forget about this move before it even gets off the ground.