Liverpool boss Brendan Rodgers says that he wants his side to bounce back from a disappointing defeat to Aston Villa by beating Ludogorets in the Champions League.
Villa came at Anfield as outsiders on Saturday, but their defensive solidarity provided them with the victory and left a number of questions being asked of Rodgers' squad.
He now wants to see a reaction from his team and their game against Ludogorets is the perfect opportunity to right some wrongs, the Reds' boss believes.
"This is a group that has shown over the time that I've been here that we have to get over disappointment and move to the next game," Rodgers said to the club's official site.
"We have to move on. Our focus now goes straight to Tuesday night.
"It will be a wonderful occasion for us to be back in Champions League football and hopefully getting over [the Villa result] by getting a win in the first group game."
Liverpool worked hard to get back into Europe's elite competition last season, where they rose to second in the Premier League, and they will be hoping to make the most of their opportunity now.
The Reds have a proud history in the Champions League, but haven't participated in it for some time and they will be looking to prove that they have the credentials to compete again this campaign.
Their opening game against Ludogorets should be a gentle introduction back into life in the competition, as they are arguably the weakest side to make it to the group-stages.
Rodgers will be hoping that a win brings some positivity back to the club, after what has been a rather worrying start to the season.
Although a 3-0 win over Tottenham Hotspur before the international break highlighted the quality of the side, they still seem to have rather stuttered out of the blocks.
Defeats to Manchester City and Villa have left fans querying whether they have enough to make it back into the top four without Luis Suarez, who departed for Barcelona last summer, and there is a growing pressure on the squad following last season's success to pick up their form.