The Gunners have been the form side this season, showing immaculate attacking football in their march to the table’s summit.
Liverpool have also shown that they need to be taken seriously this term, and are seemingly ready to challenge for a berth back in the top four once more.
Both sides recorded victories in their last outings, with Arsene Wenger’s men winning at Crystal Palace and the Reds triumphing 4-1 against West Brom at Anfield.
Following Liverpool’s impressive performance against the Baggies, many are predicting a close encounter against Arsenal.
Jordan Henderson has been a key man in Brendan Rodgers’ side, putting in solid early season performances, and has stated that Liverpool want to show the rest of England what they are capable of on Saturday.
"Confidence is very high at the minute," Henderson told the club's official website.
"We've started the season very well, but there's still room for improvement and we're still going to push and try and become better as a team.
"So hopefully we can keep doing what we've been doing and we can go to the Emirates and get a good result.
"They're all tough games in the Premier League and Arsenal have been flying of late. But so have we, so I think it will be a good game to watch and hopefully we can get a good result.
"It would send out a message to the rest of the teams that we're here and we mean business. But I think the main focus is going there and playing like we have been."
The middle battle that Henderson will be included in could well be a key element to deciding the eventual winners. He will most likely partner Steven Gerrard in the heart of the visitors’ side, and should be confident of getting the upper hand.
With Mikel Arteta suspended and Mathieu Flamini injured, the Liverpool pair will look to get the better of Jack Wilshere and Aaron Ramsey, in what should be an enthralling match-up.
If the Reds were to win the clash and take top spot, it would certainly be a real statement of intent that the Merseysiders have arrived as a serious contender once more.